Besarnya nilai Kc dan Kp adalah 0,044 dan 0,0138
Penjelasan:
Diketahui:
V = 4 L
m SO₃ = 160 gram
P total = 12 atm
n SO₃ : O₂ = 3 : 1
Ditanyakan:
Kc dan Kp
Jawab:
n SO₃ = m/Mr
n SO₃ = 160/80
n SO₃ = 2 mol
Persamaan reaksi:
2SO₃ ⇄ 2SO₂ + O₂
M 2 - -
R 2x 2x 1x
S 3x 2x 1x
2 - 2x = 3x
2 = 5x
x = 2/5
x = 0,4 mol
n SO₃ = 3x = 3 x 0,4 = 1,2 mol
n SO₂ = 2x = 2 x 0,4 = 0,8 mol
n O₂ = x = 0,4 mol
n total = 2,4 mol
[SO₃] = M /V
[SO₃] = 1,2/4
[SO₃] = 0,3 M
[SO₂] = M/V
[SO₂] = 0,8/4
[SO₂] = 0,2 M
[O₂] = M/V
[O₂] = 0,4/4
[O₂] = 0,1 M
2SO₃ ⇄ 2SO₂ + O₂
Kc = [tex]\frac{[SO_2]^2~[O_2]}{[SO_3]^2}[/tex]
Kc = [tex]\frac{(0,2)^2~(0,1)}{(0,3)^2}[/tex]
Kc = 0,044
P SO₃ = 1,2/2,4 x 12 atm
P SO₃ = 6 atm
P SO₂ = 0,2/2,4 x 12 atm
P SO₂ = 1 atm
P O₂ = 0,1/2,4 x 12 atm
P O₂ = 0,5 atm
Kp = [tex]\frac{(pSO_2)^2~(pO_2)}{(pSO_3)^2}[/tex]
Kp = [tex]\frac{(1)^2~(0,5)}{(6)^2}[/tex]
Kp = 0,0138
Pelajari lebih lanjut
Tetapan kesetimbangan konsentrasi (Kc) https://brainly.co.id/tugas/8581519, https://brainly.co.id/tugas/14193984
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